Question

Factorize : x3+3x2y+3xy2+2y2

Answer 1

Correct question be :

Factorize x³ + 3x²y + 3xy² + 2y³

Answer :

    Now, x³ + 3x²y + 3xy² + 2y³

    = ( x³ + 3x²y + 3xy² + y³ ) + y³

    = ( x + y )³ + y³

    = ( x + y + y ) { ( x + y )² - ( x + y ) y + y² }

    = ( x + 2y ) ( x² + 2xy + y² - xy - y² + y² )

    = ( x + 2y ) ( x² + xy + y² )

which is the required factorization

Algebraic Identities :

  ( a + b )³ = a³ + 3a²b + 3ab² + b³

  a³ + b³ = ( a + b ) ( a² - ab + b² )

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Answer 2

Same by that mark as brainliest user

thank you