Question

Factorize:

x3 +5x2 -2x -4
x3 +7x2 +7x +1
x3 + 4x2 +11x +8
3a3 +2a +5
5a3 +11a2 +4a -2
4a4 +11a3 -47a3 -9a +5
2x3 -x2 +9x +5
3x3 +10x2 -7x -20
p3 +6p2 +12p +7
x2 +x -(a +1)(a+2)
x2 -bx -(a +3b)(a +2b)
(a2 -b2)x2 +2ax +1
x3 -2(a +1/a)x +4
x2 -(2x(a2 +1)/a2 -1) +1

Please solve this on a piece of paper by 1700hrs IST on 20th Jan 2021. Please this a humble request, and if you are able to fulfill my request, I'll mark you as BRAINLIEST...

Answer 1

Answers

most convenient solution is

cubic equations are in format ax^3+bx^2+cx+d=0

now find all factors of d

like in your question 1

d=4

so factors are 1,2,4

check for what factor the equation is satisfied

here at 1 equation satisfies

so one is (x-1)

now divide x^3+5x^2-2x-4 by x-1

=> (x-1)(division result )

this division result will be in quadratic form , so factorize it and you will get result