Math, asked by Mihir7, 1 year ago

Factorize: x³ - 7x +6

Ayeshabb: It's very easy

Anonymous: check the question again....

Anonymous: mihir were u going to base coaching classes last year??

Anonymous: ayesha see the question is different its not easy......u can not factorise it just like that...

ElsAnna: it cant be factorised it should be x^2

Anonymous: ya that's y i tolf to check the question again......

ElsAnna: see the answer below i didnt understand it

Anonymous: me too its not correct too.......

Mihir7: Its given in Page No. 5.25 Q.8 in RD Sharma Class 9

Answers

Answered by sureshbhat47

x3 - 7x + 6 = x3 - 8 - 7x + 14 = ( x - 2 ) ( x2 + 2x + 4 ) - 7 ( x - 2 )

= ( x - 2 ) ( x2 + 2x +4 - 7 )

= ( x - 2 ) ( x2 + 2x - 3 )

= ( x - 2 ) ( x + 3 ) ( x - 1)

sureshbhat47: a3 - b3 = ( a - b ) ( a2 + ab + b2 )

Answered by nilesh102

$</p><p></p><p>\mathfrak{ \huge\underline \red{solution : - }} \\ \\ = > \red{ {x}^{3} - 7x + 6} \\ \\ put \: - {x}^{2} + {x}^{2} \\ \\ = > \red{ {x}^{3} - {x}^{2} + {x}^{2} - 7x +6 } \\ \\ = > \red{ {x}^{3} - {x}^{2} + {x}^{2} - 7x +6 } \\ \\ \underline{now} \\ \\ = > \red{ ({x}^{3} - {x}^{2} )+ ({x}^{2} - 7x +6 ) } \\ \\ = > { {x}^{2} (x - 1) + ({x}^{2} - x - 6x+6 ) } \\ \\ = > { {x}^{2} (x - 1) + (x(x -1) - 6 ( x - 1 ) )} \\ \\ = > { {x}^{2} (x - 1) + (x -6) ( x - 1)} \\ \\ now \\ \\ = > {( {x}^{2} + (x - 6) )(x -1) } \\ \\ \fbox{we \: take \: (x - 1) \: common} \\ \\ i.e. \\ \\ = > (x - 1) ({x}^{2} + x - 6) \\ \\ = > (x - 1) \: \: \: \: ({x}^{2} - 3 x + 2x- 6) \\ \\ = > (x - 1) \: \: \: \: (x (x - 3) + 2 (x- 3) ) \\ \\ = > \fbox{ \red{(x - 1)(x + 2)(x - 3)}} \\ \\ \\ \fcolorbox{red}{white}{i \: hope \: it \: helps \: you.}$

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