Question

factorize x3+x2+2x+8​

Answer 1

Answer:

(x +2)(x^2-x+4) are the factors of

X^3+x^2+2x +8

Answer 2

Answer:

The factors of the constant polynomial 8 are +-1,+-2,+-4,+-8

Now with trial and error method we get x= -2

p(-2)= (-2)^3+(-2)^2+2×(-2)+8

= -8+4-4+8

= 0

Now with long division method we get (x^3+x^3+2x+8)÷(x+2)=x^2-x+4

Therefore factors of p(x) are (x+2)(x^2-x+4)

Hope it helps.

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