factorize x³-x²+x-1
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Answer:
hello mate
let
x³ - x² + x -1 = 0
x² (x -1) + 1 ( x - 1) = 0
(x² + 1) ( x - 1) =0
x² + 1 = o or x -1 = 0
x = √-1 or x = 1
neglecting √ -1 or iota as it is not permitted to put - sign inside the root
thus final answer
x = 1
thanks :)
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