Question

factorize
x3y3-y3+8x3-8​

Answer 1

Step-by-step explanation:

The solve is attached for reference.

if my answer is correct then plzz mark me the brainliest.

Answer 2

$Given \: x^{3}y^{3} - y^{3}+8x^{3}-8$

$= y^{3}(x^{3} - 1) + 8(x^{3} - 1 )$

$= (x^{3} - 1)( y^{3} + 8 )$

$= (x^{3} - 1^{3})( y^{3} + 2^{3})$

/* By algebraic identity */

$\boxed{ \pink{ a^{3} - b^{3} = (a-b)(a^{2}+ab+b^{2})}}$

$= (x-1)(x^{2} + x \times 1 + 1^{2} ) (y-2)(y^{2} + y \times 2 + 2^{2} )$

$= (x-1)(x^{2} + x + 1) (y-2)(y^{2} + 2y + 4 )$

Therefore.,

$\red{ Factors \:of \: x^{3}y^{3} - y^{3}+8x^{3}-8}$

$\green {= (x-1)(x^{2} + x + 1) (y-2)(y^{2} + 2y + 4 ) }$

•••♪