Question

Factorize : x6 + 32x3 - 64

Answer 1

@

x6 + 32x3 -64
=> (x²)³ + (2x)³ + (-4)³ - 3(x²)(2x)(-4)
Lets see is it right or not
(x²)³ = x6

(2x)³ = 8x³ & -3(x²)(2x)(-4) = 24x³
so , (2x)³-3(x²)(2x)(-4) = 8x³+24x³ = 32x³

(-4)³ = -64

Now,
=> (x²)³ + (2x)³ + (-4)³ - 3(x²)(2x)(-4)
=> (x²+2x-4) ( x⁴+4x²+16-2x³+8x+4x² ) Ans

@:-)