Question

Factorize: xcube-3x2 - X+3.​

Answer 1

$</p><p></p><p>\huge{\bf{\red{\underline{\underline{Answer:}}}}} \\ \bf{=x^3-3x^2-x+3} \\ \bf{=x^3-x-3x^2+3} \\\bf{ =x(x^2-1)-3(x^2-1) } \\ \bf{=(x-3)(x^2-1)} \\ \bf{=(x-3)[(x)^2-(1)^2]} \\ \bf{=(x-3)[(x-1)(x+1)]} \\ Here \: we \: have \: used \: a^2-b^2=(a+b) (a-b) \\ \huge{\tt{(x-3)(x+1)(x-1) }}$

Answer 2

Answer:

for the in bo x po w er u have to comp lete 3000 ans after u can in bo x to any one.