Question

Factorize y2

- 5y + 6​

Answer 1

Step-by-step explanation:

y^2-5y+6

= y^2-2y-3y+6

= y(y-2) -3(y-2)

=(y-3)(y-2)

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Answer 2

Given :-

$y {}^{2} - 5y + 6 = 0$

What to find out =Roots of the equation?

Solution :-

Factorise by splitting middle term

$y {}^{2} - 3y - 2y + 6 = 0 \\ \\ y(y - 3) - 2(y - 3) = 0 \\ \\ (y - 3)(y - 2) = 0$

Now split it into possible cases

$(y - 3) = 0 \\ \\ (y - 2) = 0$

Hence,

$y_1 = (3) \\ \\ y_2 =( 2)$