Question

Factorize : y2 + 7y +12

Answer 1

Answer:

hey mate here is your answer

Step-by-step explanation:

Use the sum-product pattern

2+7+12

y^{2}+{\color{#c92786}{7y}}+12y2+7y+12

2+4+3+12

y^{2}+{\color{#c92786}{4y}}+{\color{#c92786}{3y}}+12y2+4y+3y+12

2 . Common factor from the two pairs

2+4+3+12

y^{2}+4y+3y+12y2+4y+3y+12

(+4)+3(+4)

y(y+4)+3(y+4)y(y+4)+3(y+4)

3 Rewrite in factored form

(+4)+3(+4)

y(y+4)+3(y+4)y(y+4)+3(y+4)

(+3)(+4)

(y+3)(y+4)(y+3)(y+4)

Solution

(+3)(+4)

Answer 2

Answer:

y²+7y+12

y²+3y+4y+12

y(y+3) 4(y+3)

(y+4)(y+3)

=> y+4=0

y= -4

=> y+3= 0

y= -3

follow me.......