Question

factorize y³-27
Answer ​

Answer 1

Answer:

${y}^{3} - 27 = 0 \\ \: \: \: \: \: \: \: \: \: \: \: = > {y}^{3} = 27 = {3}^{3} \\ = > y = 3$

Hope it's helpful for you

Answer 2

Answer:

${ \underline{ \boxed{ \tt{ \green{(y - 3)(y {}^{2} + 3y + 9)}}}}}$

Step-by-step explanation:

Rewrite y³ - 27 as y³ - 3³. The difference of cubes can be factored using the rule: a³ - b³ = (a - b)(a² + ab + b2). Polynomial y² + 3y + 9 is not factored since it does not have any rational roots.