Factorizing by regrouping (2a-3b) (m+n) +(3a-2b) (m+n)
Answers
Answered by
1
Answer:
Step-by-step explanation:
Attachments:
Answered by
0
Question :- Factorise (2a-3b)(m+n)+(3a-2b)(m+n) by regrouping ?
Solution :-
→ (2a - 3b)(m + n) + (3a - 2b)(m + n)
→ 2am + 2an - 3bm - 3bn + 3am + 3an - 2bm - 2bn
regrouping the likes terms, we get,
→ (2am + 3am) + (2an + 3an) - (3bm + 2bm) - (3bn + 2bn)
→ 5am + 5an - 5bm - 5bn
→ (5am + 5an) - (5bm + 5bn)
→ 5a(m + n) - 5b(m + n)
→ 5(m + n)(a - b) (Ans.)
Learn more :-
if a nine digit number 260A4B596 is divisible by 33, Then find the number of possible values of A.
https://brainly.in/question/32686002
if n is an integer such that 1nn352 is a six digit number
https://brainly.in/question/26617043
Similar questions