Question

factors of 1 - 10x + 25x²​

Answer 1

(25x²-1)+(1+5x)²

(25x²-1)+(1+5x)²=[(5x)²-(1)²]+[1+5x]²

(25x²-1)+(1+5x)²=[(5x)²-(1)²]+[1+5x]²=(5x-1)(5x+1)+(1+5x)(1+5x)

(25x²-1)+(1+5x)²=[(5x)²-(1)²]+[1+5x]²=(5x-1)(5x+1)+(1+5x)(1+5x)take 1+5x common

(25x²-1)+(1+5x)²=[(5x)²-(1)²]+[1+5x]²=(5x-1)(5x+1)+(1+5x)(1+5x)take 1+5x common=(1+5x)[(5x-1)+(5x+1)]

(25x²-1)+(1+5x)²=[(5x)²-(1)²]+[1+5x]²=(5x-1)(5x+1)+(1+5x)(1+5x)take 1+5x common=(1+5x)[(5x-1)+(5x+1)]=(1+5x)(5x-1+5x+1)

(25x²-1)+(1+5x)²=[(5x)²-(1)²]+[1+5x]²=(5x-1)(5x+1)+(1+5x)(1+5x)take 1+5x common=(1+5x)[(5x-1)+(5x+1)]=(1+5x)(5x-1+5x+1)=(1+5x)(10x).

(25x²-1)+(1+5x)²=[(5x)²-(1)²]+[1+5x]²=(5x-1)(5x+1)+(1+5x)(1+5x)take 1+5x common=(1+5x)[(5x-1)+(5x+1)]=(1+5x)(5x-1+5x+1)=(1+5x)(10x).so, factors of given eq are 10x & 1+5x.

(25x²-1)+(1+5x)²=[(5x)²-(1)²]+[1+5x]²=(5x-1)(5x+1)+(1+5x)(1+5x)take 1+5x common=(1+5x)[(5x-1)+(5x+1)]=(1+5x)(5x-1+5x+1)=(1+5x)(10x).so, factors of given eq are 10x & 1+5x.here is the answer of your question may be this will help you...

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Answer 2

I Think it will come....