Question

Factors of 1 + 64x ³

Answer 1

1 + 64x^3

= 1^3 + (4x)^3

using identity

a cube + b cube

(1+4x)(1^2+(4x)^2 + 1*4x)

= (1+4x)(1+16x^2+4x)

$...$

Answer 2

Answer:

(1+4x)(1-4x+16$x^{2}$)

Step-by-step explanation:

1+64$x^{3}$

=$1^{3} +(4x)^{3}$

=(1+4x)(1-4x+16$x^{2}$)