Math, asked by viiifnityasinghal, 3 months ago

Factors of 1-(b-c)² *
1 point
(1-b-c)(1-b-c)
(b-c-1)(b+c-1)
(1+b-c)(1-b+c)
none​

Answers

Answered by bagkakali
5

Answer:

1-(b-c)^2

=(1)^2-(b-c)^2

={1+(b-c)} {1-(b-c)}

=(1+b-c)(1-b+c)

Answered by thakurrohit45
3

Answer:

(1+b-c)(1-b+c)

Step-by-step explanation:

1

2

−(b−c)

2

usingx

2

−y

2

=(x+y)(x−y)

(1+b−c)(1−b+c)

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