Question

factors of (1-x²) are​


plz fast it's urgent

Answer 1

Answer:

(1+x) (1-x)

Step-by-step explanation:

Since both terms are perfect squares, factor using the difference of squares formula,  

a^2-b^2 = (a+b) (a-b) where a= 1 and b=x

hence (1+x)(1-x) are the factors

hope this is helpful... :)

Answer 2

Answer:

$a ^{2} - b^{2} = (a + b)(a - b)$

therefore ,

$(1 - x ^{2}) \\ = 1^{2} - x^{2} \\ = (1 + x)(1 - x)$

hence the factors are 1+x and 1-x