Factors of 12p² - 27q² are
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Answered by
0
(√12p+√27q)(√12p-√27q)
Root is only for numbers, not for p and q.
Hope this helps.. Have a good day ahead...
Answered by
1
Answer:
12p²-27q²
12(6p)²-(54)²
[(6p)²-(9q)²]
(6p+9q)(6p-9q)
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