Question

factors of (16y2 – 1)

Answer 1

Answer:

(16y^2-1)

= (4y+1)(4y-1)

Answer 2

$16 {y}^{2} - 1 \\ = {(4y)}^{2} - {(1)}^{2} \\ = (4y + 1)(4y - 1)$

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