Question

factors of (16y²-2)+(1-4y)² ​

Answer 1

Answer:

$factors : \\ (16 {y}^{2} - 2) + (1 - 4y {)}^{2} \\ =( 16 {y}^{2} - 2) +( (1 {)}^{2} + 2(1)( - 4y) + ( - 4y {)}^{2} ) \\ = 16 {y}^{2} - 2 + 1 - 8y + 16 {y}^{2} \\ = 32 {y}^{2} - 8y - 1$