factors of 27xcube+1
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27x³ + 1
1 is a cube of 1
(3x)³ + (1)³
Using the identity a³+b³ = (a+b)(a²+b²-ab)
(3x+1){(3x)² + (1)² - 3x × 1}
(3x+1)(9x² + 1-3x)
ANSWER:-
(3x+1)(9x²+1-3x)
Hope it helps...
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