Math, asked by gafrul2017, 11 months ago

factors of 2p^2-11p+12​

Answers

Answered by shravni89
1

Answer:

Simplifying

2p2 = -11p + -12

Reorder the terms:

2p2 = -12 + -11p

Solving

2p2 = -12 + -11p

Solving for variable 'p'.

Reorder the terms:

12 + 11p + 2p2 = -12 + -11p + 12 + 11p

Reorder the terms:

12 + 11p + 2p2 = -12 + 12 + -11p + 11p

Combine like terms: -12 + 12 = 0

12 + 11p + 2p2 = 0 + -11p + 11p

12 + 11p + 2p2 = -11p + 11p

Combine like terms: -11p + 11p = 0

12 + 11p + 2p2 = 0

Factor a trinomial.

(4 + p)(3 + 2p) = 0

Subproblem 1

Set the factor '(4 + p)' equal to zero and attempt to solve:

Simplifying

4 + p = 0

Solving

4 + p = 0

Move all terms containing p to the left, all other terms to the right.

Add '-4' to each side of the equation.

4 + -4 + p = 0 + -4

Combine like terms: 4 + -4 = 0

0 + p = 0 + -4

p = 0 + -4

Combine like terms: 0 + -4 = -4

p = -4

Simplifying

p = -4

Answered by praja450512
3

Answer:

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