Math, asked by ravichandracharan, 5 months ago

factors of (2x^2-3x)^2-4(2x^2-3x)-5​

Answers

Answered by ShreyaKumari5577
1

Step-by-step explanation:

( 2 2 − 3 ) 2 − 4 ( 2 2 − 3 ) − 5

(2x^{2}-3x)^{2}-4(2x^{2}-3x)-5

(2x2−3x)2−4(2x2−3x)−5 ( 2 2 − 3 ) ( 2 2 − 3 )− 4 ( 2 2 − 3 ) − 5

( 2 2 − 3 ) ( 2 2 − 3 ) − 4 ( 2 2 − 3 ) − 5

2 ( 2 2 − 3 )⋅ 2 − 3 ( 2 2 − 3 ) − 4 ( 2 2 − 3 ) − 5

4 4 − 1 2 3 + 2 + 1 2 − 5

HOPE U NDERSTOOD....❤❤❤❤

PLZ MARK ME AS BRAINLIST

Similar questions