Question

factors of (2x²-3x-2)(2x²-3x)-63​

Answer 1

Step-by-step explanation:

let(2x2−3x)=t

(t - 2)t - 63(t−2)t−63

{t}^{2} - 2t - 63t2−2t−63

{t}^{2} - 9t + 7t - 63t2−9t+7t−63

t(t - 9) + 7(t - 9)t(t−9)+7(t−9)

(t + 7)(t - 9)(t+7)(t−9)

(2 {x}^{2} - 3 + 7)(2 {x}^{2} - 3x - 9)(2x2−3+7)(2x2−3x−9)

(2 {x}^{2} - 3x + 7)(2 {x}^{2} - 6x + 3x - 9(2x2−3x+7)(2x2−6x+3x−9

(2 {x}^{2} - 3x + 9) \: (2x(x - 3) + 3(x - 3))(2x2−3x+9)(2x(x−3)+3(x−3))

(2 {x}^{2} - 3x + 7) \: (2x + 3)(x - 3)(2x2−3x+7)(2x+3)(x−3)

Answer 2

I hope this answer is helpful...