Math, asked by akashdeep391902, 3 months ago

Factors of 32x³y³ - 98xy are​

Answers

Answered by Anonymous
0

Answer:

  • Factors of 32x³y³ - 98xy are

Step-by-step explanation:

  • Your maths problem
  • 3
  • 2
  • 3
  • 3
  • 9
  • 8
  • What are all the factors of 98?
  • The factors of 98 are 1, 2, 7, 14, 49, 98.
  • hope it helps you!
Answered by XxMissKhushixX
4

Answer:

The H.C.F. of 2, 10 and 8 is 2.

The H.C.F. of 2, 10 and 8 is 2.The common variables appearing are m and n.

The H.C.F. of 2, 10 and 8 is 2.The common variables appearing are m and n.The smallest power of m appearing in 3 monomials = 1

The H.C.F. of 2, 10 and 8 is 2.The common variables appearing are m and n.The smallest power of m appearing in 3 monomials = 1The smallest power of n appearing in 3 monomials = 2

The H.C.F. of 2, 10 and 8 is 2.The common variables appearing are m and n.The smallest power of m appearing in 3 monomials = 1The smallest power of n appearing in 3 monomials = 2Therefore, monomials of common variables with the smallest power = mn2

The H.C.F. of 2, 10 and 8 is 2.The common variables appearing are m and n.The smallest power of m appearing in 3 monomials = 1The smallest power of n appearing in 3 monomials = 2Therefore, monomials of common variables with the smallest power = mn2Therefore, H.C.F. of 2m3n2, 10m2n3, 8mn4 is 2mn2.

XxMissKhushixX

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