Factors of 32x³y³ - 98xy are
Answers
Answer:
- Factors of 32x³y³ - 98xy are
Step-by-step explanation:
- Your maths problem
- 3
- 2
- 3
- 3
- −
- 9
- 8
- What are all the factors of 98?
- The factors of 98 are 1, 2, 7, 14, 49, 98.
- hope it helps you!
Answer:
The H.C.F. of 2, 10 and 8 is 2.
The H.C.F. of 2, 10 and 8 is 2.The common variables appearing are m and n.
The H.C.F. of 2, 10 and 8 is 2.The common variables appearing are m and n.The smallest power of m appearing in 3 monomials = 1
The H.C.F. of 2, 10 and 8 is 2.The common variables appearing are m and n.The smallest power of m appearing in 3 monomials = 1The smallest power of n appearing in 3 monomials = 2
The H.C.F. of 2, 10 and 8 is 2.The common variables appearing are m and n.The smallest power of m appearing in 3 monomials = 1The smallest power of n appearing in 3 monomials = 2Therefore, monomials of common variables with the smallest power = mn2
The H.C.F. of 2, 10 and 8 is 2.The common variables appearing are m and n.The smallest power of m appearing in 3 monomials = 1The smallest power of n appearing in 3 monomials = 2Therefore, monomials of common variables with the smallest power = mn2Therefore, H.C.F. of 2m3n2, 10m2n3, 8mn4 is 2mn2.