Question

factors of 3x square +11x+6​

Answer 1

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$3 {x}^{2} + 11x + 6$

$= 3 {x}^{2} + 9x + 2x + 6$

$= 3x(x + 3) + 2(x + 3)$

$= (x + 3)(3x + 2)$

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Answer 2

Answer:

$\boxed{\sf (x + 3)(3x + 2)}$

Step-by-step explanation:

$\sf Factor \: the \: following: \\ \sf \implies 3{x}^{2} + 11x + 6 \\ \\ \sf The \: coefficient \: of \: {x}^{2} \: is \: 3 \: and \: the \: constant \\ \sf term \: is \: 6. \: The \: product \: of \: 3 \: and \: 6 \: is \: 18. \\ \sf The \: factors \: of \: 18 \: which \: sum \: to \: 11 \: are \\ \sf 2 \: and \: 9. \\ \\ \sf So, \\ \sf \implies 3 {x}^{2} + (9 + 2)x + 6 \\ \\ \sf \implies 3{x}^{2} + 9x + 2x + 6 \\ \\ \sf \implies 3x(x + 3) + 2(x + 3) \\ \\ \sf \implies (x + 3)(3x + 2)$