factors of 4x^2+4x-1
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Answered by
2
(2x+1-√2)(2x+1+√2)
dis is ur answer
and it will come if u do +1 and -1 in the question and solve further.....
dis is ur answer
and it will come if u do +1 and -1 in the question and solve further.....
SarthakSyal:
bcz if u will do +1 nd -1 then u will get 4x²+4x +1 -2
nd it can be ritten as (2x+1)² - 2
Ok
nd 2 can be riiten as (√2)² and now by identity a²-b²
Ok
(2x+1)²-(√2)² can be ritten as (2x+1-√2)(2x+1+√2)
hope now it goes clear to u
Yes
hmm
Hmmm
Answered by
2
4x^2 + 4x - 1
4x^2 + (2+2)x - 1
4x^2+ 2x + 2x - 1
2x (2x + 1) +1 (2x+1)
(2x+1) (2x+1)
2x = -1, 2x = -1
x = -1/2, x = -1/2
4x^2 + (2+2)x - 1
4x^2+ 2x + 2x - 1
2x (2x + 1) +1 (2x+1)
(2x+1) (2x+1)
2x = -1, 2x = -1
x = -1/2, x = -1/2
Ok
0= a²x² + 4x² + 12x + 4a
now acc to the formula i told u
12x can be written as only 2×a×b that is 2×2×2
so a= 2
nd if we place value of 2 in the question in place of a
then we will havw 8x²+16x+8
which can be written as ( x+1)
sorry....(x+1)(8x+1)
which means our ans is correct bcz it forms a perfect square
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