factors of 4x^2-9y^2
nainamishra1:
2x^2-3y^2
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4x^2 - 9y^2
=> (2x)^2 - (3y)^2
Using identity, a^2 - b^2 = (a+b) (a-b), we get
=> (2x +3y)(2x - 3y)
=> (2x)^2 - (3y)^2
Using identity, a^2 - b^2 = (a+b) (a-b), we get
=> (2x +3y)(2x - 3y)
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Hope it will help u much
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