Math, asked by shri1824, 4 months ago

Factors of 4y^{2}-12y+9

Answers

Answered by aksharasharma490
1

Answer:

• 4y^[2]-12y+9

• (2y)^2-12y+3^2

• (2y)^2-2×2y×3+3y^2

• (2y)^2+(3)^2-2×2y×3

[using (a-b)^2=a^2+b^2-2ab. Hence,a=2y,b=3]

= (2y-3)^2

Answered by indhumathi2005
0

Answer:

y =  \frac{3}{2}

Step-by-step explanation:

4y {}^{2}  - 12y + 9

By splitting the middle term,

4y {}^{2}  - 6y - 6y + 9

2y(2y - 3) \:  \:  \: - 3(2y - 3)

(2y - 3) \:  \:  \:  \:  \: (2y - 3)

y =  \frac{3}{2}  \:  \:  \:  \:  \:

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