factors of 64a²+1 are
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Answer:
64a²+1
=(8a)²+(1)²
=(8a+1)²-2×8a×1
=(8a+1)²-16a
Answered by
1
64a^2 + 1
=(8a) ^2 + (1)^2
=(8a+1)^2 - 2*8a*1
=(8a+1)^2 - 16a
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