Question

factors of (81 x^4-25) are
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

$8 1{x}^{4} - 25 = 0\\ ( {a}^{2} - {b}^{2} = (a + b)(a -b))\\0 = {(9 {x}^{2} )}^{2} - {(5)}^{2} \\ 0 = (9x + 5)(9x - 5) \\ 9x + 5 = \frac{0}{9x - 5} \\ 9x + 5 = 0 \\ 9x = - 5 \\ x = \frac{ - 5}{9} \\ or \\ 9x - 5 = \frac{0}{9x + 5} \\ 9x - 5 = 0 \\ 9x = 5 \\ x = \frac{5}{9}$

Thus the factors are

$\frac{\frac{5}{9} \: and \: \frac{-5}{9}}{}$