Question

Factors of 8x³+ y³ are:
A. (2x + y) (4x² - 2xy + y²)
B. (2x + y) (4x² + 2xy + y²)
C. (2x - y) (4x² - 2xy + y²)
D. (2x + y) (4x² - 2xy - y²)​

Answer 1

Answer:

(v) (3 - 2x)(3 + 2x) = (3)² - (2x)² [a² - b² = (a + b)(a - b)] = 9 - 4x² ... (i) 9x² + 6xy + y² = (3x)² + 2 x 3x x y + y² [(a + b)² = a² + b² - ab] = (3x + y)² ... (ii) 2x² + y² + 8z² – 2√2xy + 4√2 yz – 8xz By indentity [(a + b + c)² = a² + b² + c² + 2ab + 2bc ... (i) x³ + y³ = (x + y) (x² – xy + y²) Using R.H.S (x + y) (x² – xy + y²) = x³ - x²y + xy² + yx² - xy² + y³ ...

Step-by-step explanation:

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Answer 2

Maybe (C) is correct


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