Question

factors of a^2 x^2+2ax+1 are​

Answer 1

Answer:

a2x2+2ax+1=0 

No solutions found

Step by step solution :

Step  1  :

Trying to factor a multi variable polynomial :

 1.1    Factoring    a2x2 + 2ax + 1 

Try to factor this multi-variable trinomial using trial and error 

 Found a factorization  :  (ax + 1)•(ax + 1)

Detecting a perfect square :

 1.2    a2x2  +2ax  +1  is a perfect square 

 It factors into  (ax+1)•(ax+1)

which is another way of writing  (ax+1)2

How to recognize a perfect square trinomial:  

 • It has three terms  

 • Two of its terms are perfect squares themselves  

 • The remaining term is twice the product of the square roots of the other two terms

hope it helps you

Answer 2

a^2 x^2 + 2ax + 1

= a^2 x^2 + ax + ax +1

= ax(ax +1 ) +1(ax + 1)

=(ax +1)(ax+1)