Question

Factors of a²+5a+6
please help me​

Answer 1

Answer :

Soln: a²-5a+6 = 0 [ '0′ is b/z, every quadratic eqn.s contains 0)

a²-6a+a+6 = 0 [b/z, by splitting 6 into 6×1 as it should give a constant by adding or subtracting them both]

Now, take the common terms out by grouping the terms into two which we can get two common terms. So, we get

a(a-6)-1(a-6) = 0

(a-6)(a-1) = 0

Now, we know that principle that, “if a.b = 0, then a = 0 or b = 0.” Therefore, from this we can write it as,

(a-6) = 0 or (a-1) = 0

a = 0+6 or a = 0+1

Therefore, a = 6 or a = 1 as, a quadratic eqn has two roots.

So, this is the method of factorisation for your problem. Thank you.

Answer 2

Step-by-step explanation:

This is the answer because I believe this answer