Question

factors of a²-a-12
give whole procedure​

Answer 1

Answer:

a² - a -12.

we have to select 2 digit which on multiplication gives us -12 ( constant of a² and c which is -12) and on addition it gives -1 (constant of a)

a² -a -12

= a² +3a - 4a -12

now take common

= a ( a +3 ) -4 ( a +3)

= ( a-4 ) ( a +3 )

a-4=0. a+3=0

a = 4. a = -3

factors are 4, -3

hope its help

Answer 2

Given:

• Factors of a²-a-12

To find:

• The factors?

Solution:

➸ a²-a-12

➸ a²-3a-4a-12

➸ a(a+3)-4(a+3)

➸(a+3) (a-4)

Answer:

• The factors are (a+3) (a-4)

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