Math, asked by satishaccounts5031, 11 hours ago

Factors of b³+b-3b²-3 are:

Answers

Answered by kukukumari1985
0

Answer:

(b-3)(b²+1)

Step-by-step explanation:

b³+b-3b²-3

=b(b²+1)-3(b²+1)

=(b-3)(b²+1)

Answered by misscutie94
2

Answer:

Question :-

➪ b³ + b - 3b² - 3

Solution :-

➪ b³ + b - 3b² - 3

➭ b(b² + 1) - 3(b² + 1)

➭ (b² + 1) (b - 3)

∴ The value of b³ + b - 3b² - 3 is

( + 1) (b - 3)

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