Factors of b³+b-3b²-3 are:
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0
Answer:
(b-3)(b²+1)
Step-by-step explanation:
b³+b-3b²-3
=b(b²+1)-3(b²+1)
=(b-3)(b²+1)
Answered by
2
Answer:
Question :-
➪ b³ + b - 3b² - 3
Solution :-
➪ b³ + b - 3b² - 3
➭ b(b² + 1) - 3(b² + 1)
➭ (b² + 1) (b - 3)
∴ The value of b³ + b - 3b² - 3 is
(b² + 1) (b - 3)
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