Factors of the polynomial are (a) (3t - 8 )(t+1) (b) (3t + 8 )(t+1). (c) (3t + 8 )(t -1) (d) none
Answers
Answered by
0
Step-by-step explanation:
t2−3,2t4+3t3−2t2−9t−12
Remainder is 0, hence t2−3 is a factor of 2t4+3t3−2t2−9t−12
(ii) x2+3x+1,3x4+5x3−7x2+2x+2
Remainder is 0, hence x2+3x+1 is a factor of 3x4+5x3−7x2+2x+2
(iii) x3−3x+1,x5−4x3+x2+3x+1
Remainder is 2, hence x3−3x+1 is not a factor of x5−4x3+x2+3x+1
Similar questions