Question

Factors of the polynomial p(x) = 16x2 -8x+1 are *

1 point

(4x+1)(4x-1)

(4x-1)(4x-1)

(4x+1)(4x+1)

None of these

​

Answer 1

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$16x {}^{2} - 8x + 1$

$16x {}^{2} - 4x - 4x + 1$

$4x(4x - 1) - 1(4x - 1)$

$(4x - 1)(4x - 1)$

Answer 2

HERE IS YOUR ANSWER MATE.....;

$= > 16x {}^{2} - 8x + 1 = 0$

$= > 16x {}^{2} - 4x - 4x + 1 = 0$

$= > 4x(4x - 1) - 1(4x - 1) = 0$

$(4x - 1)(4x - 1) = 0$

$x = \frac{1}{4}$

$x = \frac{1}{4}$

HOPE ITS HELPFUL.....:-)