Math, asked by shinchan3563, 11 months ago

factors of the polynomial xsquare-23x+108

Answers

Answered by sonalmishra
1

 {x}^{2}  - 23x \:  + 108
d =  {b}^{2}  - 4ac
d = 529 - 432 = 97
so \: there \: are \: factors \: but \: in \\ root
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