Question

factors of x^2+ax+b are (x-7)(x+9) then find the value of a and b
and explain step by step​

Answer 1

Answer:

Multiply the both numbers.

Step-by-step explanation:

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Answer 2

Answer:

g(x)=(x-7)

0=x-7

7=x

p(x)=x^2+ax+b

p(7)=(7)^2+7a+b

0=49+7a+b

Lets 49+7a+b be equation1.

g(x)=x+9

0=x+9

-9=x

p(x)=x^2+ax+b

p(-9)=(-9)^2+a(-9)+b

0=81-9a+b

Lets 81-9a+b be equation2.

Equals both the Equation.

49+7a+b=81-9a+b

9a+7a+b-b=81-49

16a=32

a=2

Now, we have the value of a. So, put value of a in equation1 or equation2. The answer get same. So, i take equation1.

49+7a+b=0

49+7×2+b=0

49+14+b=0

63+b=0

b=-63