Question

Factors
of (x ^3- 6x^2+8x-4 )are​

Answer 1

Answer:

Hence, x = 2/√3 , 2

Step-by-step explanation :

Given,

P(x) = 3x^3 - 6x^2 + 4x - 8

On using the factorisation method, we get,

=> 3x^3 - 6x^2 - 4x + 8 = 0

=> 3x^2(x - 2) - 4(x - 2) = 0

=> (3x^2 - 4)(x - 2) = 0

Here, either, (3x^2 - 4) = 0 or (x - 2) = 0

So, for the values of x,

(3x^2 - 4) = 0

=> 3x^2 = 4

=> x^2 = 4/3

=> x = √(4/3) = 2/√3

(x - 2) = 0

=> x = 2

Hence, x = 2/√3 , 2