factors of x^3-x^2y-xy^2+y^3
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x³-x²y-xy²+y³
= x²(x-y)-y²(x-y)
= (x-y)(x²-y²)
= (x-y)(x-y)(x+y)
= (x-y)²(x+y) Ans.
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Answer:
x³ - x²y - xy² + y³
= x² ( x - y ) - y² ( x - y )
= ( x - y )( x² - y² )
= (x - y)(x + y)(x - y)
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