Question

factors of:
x^4+324y^4
with solution please​

Answer 1

Answer:

x^4 + 324

(x^2)^2 + 18^2

That would be a perfect square if the term that is twice the product of the square roots of those two terms were added. That's 2·18·x^2 or 36x^2.

So we add that between those terms and then subtract it. That's the same as adding 0:

(x^2)^2 + 36x^2 + 18^2 - 36x^2

Factor the first three terms as (x^2 + 18)(x^2 + 18) or (x^2 + 18)^2

(x^2 + 18)^2 - 36x^2

That is the difference of two perfect squares:

[(x^2 + 18) - 6x][(x^2 + 18) + 6x]

[x^2 + 18 - 6x] [x^2 + 18 + 6x]

(x^2 - 6x + 18) (x^2 + 6x + 18)..

Step-by-step explanation:

Hi....

Hope it helps you......