Question

factors of x²-x-20 are? how to solve

Answer 1

here you go ☆☆

${x}^{2} - 5x + 4x - 20$

$x(x - 5) \: + 4(x - 5)$

$(x + 4) \: (x - 5)$

$eiter \\ x + 4 = 0 \\ x = - 4 \\ or \\ x - 5 = 0 \\ x = 5$

hope it helps you.....

Answer 2

Answer
The given expression is x^2-x-20
Find two numbers whose
sum = -x
and product = x^2×20
=20x^2
the numbers are -5 and -4
x^2-5x+4x-20
x(x-5)+4(x-5)
(x-5)(x+4)