Question

factors of x³-2x²-5x+6​

Answer 1

Answer:

for a cubic equaiton you need to take guesses at first root so try 1 for x and we get

1^3 - 2(1^2) - 5(1) + 6 =

1 - 2 - 5 + 6 =

- 1 + 1 = 0 so 1 is a root and can be written as x - 1 now do long division

................x^2 - x - 6

................x^3 - 2x^2 - 5x + 6

x - 1.........x^3 - x^2

.......................- x^2 - 5x

......................- x^2 + x

................................- 6x + 6

................................- 6x + 6

so we have (x - 1)(x^2 - x - 6) as factors the second term can factored further and we get

(x - 1)(x - 3)(x + 2)

Hope This Helps :)

Answer 2

Step-by-step explanation:

I hope it will help you,