Question

factors please

x²+2x-8​

Answer 1

Step-by-step explanation:

Factoring  x^2+2x-8 

The first term is,  x^2  its coefficient is  1 .

The middle term is,  +2x  its coefficient is  2 .

The last term, "the constant", is  -8 

Step-1 : Multiply the coefficient of the first term by the constant   1 • -8 = -8 

Step-2 : Find two factors of  -8  whose sum equals the coefficient of the middle term, which is   2 .

       -2   +   4   =   2   

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -2  and  4 

                     x2 - 2x + 4x - 8

Step-4 : Add up the first 2 terms, pulling out like factors :

                    x • (x-2)

              Add up the last 2 terms, pulling out common factors :

                    4 • (x-2)

Step-5 : Add up the four terms of step 4 :

                    (x+4)  •  (x-2)

             Which is the desired factorization.

(x+4) = 0 (or) (x-2) = 0.

x= -4 (or) x= 2......

Answer 2

Thnks for asking question....

Solution- ...

x²+2x-8

x²+4x-2x-8

x(x+4)-2(x+4)

(x+4)(x-2)

x+4=0 x-2=0

x=0-4 x=0+2

x=(-4) x=2

Hence x=(-4,2)Ans....

Hope its helps u