factotise the following (1to9) polynomias5p2-8pq-10p+16q
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Answered by
4
5p²-8pq-10p+16q
=> 5p²-10p-8pq+16q
(rearranging the terms)
=> 5p(p-2)-8q(p-2)
(taking 5p common from first two terms i.e. 5p²,10p
and taking 8q common from next two terms i.e. 8pq+16q)
=> (p-2) (5p-8q)
hope this helps
=> 5p²-10p-8pq+16q
(rearranging the terms)
=> 5p(p-2)-8q(p-2)
(taking 5p common from first two terms i.e. 5p²,10p
and taking 8q common from next two terms i.e. 8pq+16q)
=> (p-2) (5p-8q)
hope this helps
Answered by
8
Given 5p^2 - 8pq - 10q + 16q can be written as
= 5p^2 - 10q + 16q - 8pq
= 5p(p - 2) - 8q(p - 2)
= (p-2)(5p-8q).
Hope this helps! :)
= 5p^2 - 10q + 16q - 8pq
= 5p(p - 2) - 8q(p - 2)
= (p-2)(5p-8q).
Hope this helps! :)
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