factozisation of x²-xy(1+y)+y³
Answers
Correct question :
factozisation of x²+ xy ( 1 + y ) + y³
Answer :
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Explanation :
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It can be written as,
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Take out common,
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Definition of Factorisation :
Factorization consist of writing a number or another mathematical object as a product of several factors.
So, It's Done !!
Given :
- x² - xy(1 + y) + y³
To Find :
- Factorize the expression.
Required Solution :
⇛ x² - xy(1 + y) + y³
Apply the distributive property,
⇛ x² - xy × 1 - xy + y³
Multiply -1 by 1,
⇛ x² - xy - xy × y + y³
Move y,
⇛ x² - xy - x(y × y) + y³
Multiply y by y,
⇛ x² - xy - xy² + y³
Group the first two terms and the last two term,
⇛ (x² - xy) - xy² + y³
Factor out the greatest common factor (GCF) from each group,
⇛ x(x - 1y) - y² (x - y)
Factor the polynomial by factoring out the greatest common factor x - 1y,
⇛ (x -1y) (x - y²)
Rewrite -1y as -y
⇛ (x - 1) (x - y²)
Hence Solved !
Additional Information :
✒ Factozisation :
Factorizing is to make a single term: try to write everything as products (multiplication), for example:
→ 6x² - 9x + 10 = (2x - 5) (3x - 2)
Step ① :
Find a common factor
Example:
→ 4xy + x⁴ + x = x(4x + x³ + 1)
Step ② :
Count the number of terms
(terms are separated by + or −)
If none of these methods work, re-arrange the terms, or remove brackets and start again.