Question

factozise the following algebraic expressions by splitting the middle term (X + 7) (x - 10 )+ 16​

Answer 1

Answer:

since, p(X)=(X+7)(X-10)+16

= X²+7X-10X-70+16

= X²-3X-54

Therefore,p(X)=0

X²-3X-54=0

X²-9X+6X-54=0

X(X-9)+6(X-9)=0

(X+6)(X-9)=0

X+6=0 & X-9=0

X=-6 & X= 9

Hence, the value of X be -6 & 9.

Answer 2

The correct answer is "x = -6" or "x = 9".

Step-by-step explanation:

$The \ given \ expression \ is:\\\\(x+7)(x-10)+16\\\\On \ applying \ multiplication,we \ get\\\\x(x-10)+7(x-10)+16\\\\x^2-10x+7x-70+16\\\\x^2-3x-54\\\\On \ factorizing \ the \ above \ equation,we \ get\\x^2-9x+6x-54=0\\\\x(x-9)+6(x-9)=0\\\\(x+6)(x-9)=0\\\\x+6=0\\\\x=-6\\\\x-9=0\\\\x=9$

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