Factrise x^3+6x^2+5x_12 and verify by the product of factors
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Answer:
(x+3)(x+4)(x–1)
Step-by-step explanation:
factorising x³+6x²+5x–12=p(x)
As it is cubic polynomial first check 1
when x=1
1+6+5–12=0
it is true so x–1 is factor p(x)
when p(x) is divided by x–1 quotient=x²+7x+12=q(x
when we factorise q(x)
x²+3x+4x+12
x(x+3)+4(x+3)
(x+3)(x+4)
we get (x+3)and(x+4)
thus;(x+3)(x+4)(x–1) are factors of p(x)
VERIFICATION
(x+3)(x+4)(x–1)
x³+x²(3+4–1)+x(12–3–4)+(–12)
x³+6x²+5x–12
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