Question

factrize x²+6x+8 by completing the squares​

Answer 1

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• Factorise ${x}^{2} + 6x + 8$ by completing the square method.

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${x}^{2} + 6x + 8$

$= {(x)}^{2} + 2 \times (x) \times (3) + {(3)}^{2} - {(3)}^{2} + 8$

$= {(x + 3)}^{2} - 9 + 8$

$= {(x + 3)}^{2} - 1$

$= {(x + 3)}^{2} - {(1)}^{2}$

$= (x + 3 + 1)(x + 3 - 1)$

$= (x + 4)(x + 2)$

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• $(x + 4)(x + 2)$

Answer 2

Answer:

=x^2+4x+2x+8

=x(x+4)+2(x+4)

=(x+4)(x+2)

=>x=-4,-2

Step-by-step explanation:

hope It will help you